Array Networks / Knowledgebase / How are the cache memory allocated in 8.x?

current/cache/total/max)

current - used by application.
cache  - hold by system memory cache of zone
total    - hold by system zone
max    - limitation of mbuf/clust

(total/max) * 100 = 50.91837506%

*** 306522/602898/909420/1786035 mbufs in use (current/cache/total/max)

cache memory = "frame count" * 2.25KB

For example, a box has 8GB of total memory, 2GB is allocated for cache. Here is how these numbers translate into cache frames.

Each cache frame is 2.25KB. With 2GB of cache, it is equal to 900K cache frames.

Number of cache frames * 2.25KB = Cache memory in used

Max cache frames and memory:

Max Number of cache frames: 900000

900K * 2.25KB = 2GB

Threshold when cache drain routine kicks in. The drain threshold is 3/4 * Max cache memory.

Number of cache frames: 650000

650K * 2.25kB = 1.46GB

System Memory 4 GB 4 GB 8 GB 16 GB 16 GB 32 GB 32 GB 32 GB 32 GB
Cache Size 1 GB 1 GB 2 GB 4 GB 4 GB 8 GB 8 GB 8 GB 8 GB

root 19422 8.1 1.0 849436 77024 ?? D 15Oct12 565:07.28 /ca/bin/cache

-D stands for process in disk, it may be some memory of cache ( not read/write for a long time) already swapped to disk.

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