Yeah its got to do with something possibly with the script being called
server side for the ahah load. Its tricky going through old spaghetti code.
Daemach wrote:
>
> I would try stepping through it then to see what is happening.
>
> BTW, since you are supposed to have unique IDs for every element on your
> page, you don't really need the div in the selector - #mypage should grab
> the element using getElementByID
>
>
>
> John W wrote:
>>
>> Tried than in firebug, only one instance found. Thanks for the
>> suggestion.
>>
>>
>> Daemach wrote:
>>>
>>> Do you by any chance have elements with the sameID? If you are using
>>> firebug, try going to the console and pasting in that selector -
>>> $('div#mypage') - if it returns an array with more than 1 element,
>>> there's your problem. You can mouse over the array elements and firebug
>>> will highlight the elements on your page.
>>>
>>>
>>>
>>> John W wrote:
>>>>
>>>> Hi all,
>>>>
>>>> Im in the process of updating some old javascript to utilize jquery. I
>>>> had some old javascript that used the old
>>>> document.location. For the heck of it I replaced that with a .load. It
>>>> works, and I know this may not be the best way to do this, but Im
>>>> curious why the page is drawn twice after the load? And yes I didnt
>>>> use parameters because I intended to use a GET not POST. Are there any
>>>> technique to force .load to only fire once?
>>>>
>>>> function headersearch() {
>>>>
>>>> var g,h,ch,u;
>>>>
>>>> g=document.nsearch.acct.value;
>>>> h=document.nsearch.bustype.value;
>>>> ch=document.nsearch.report_type.value;
>>>> u="parstring=1," + g + ch + "&bustype=" + h;
>>>>
>>>> if(ch=="bud")
>>>> {
>>>> $('div#mypage').load('mypage.html?' + u);
>>>> return false;
>>>> }
>>>> else
>>>> {
>>>> $('div#mypage').load('mypage.html');
>>>> return false;
>>>> }
>>>> }
>>>>
>>>
>>>
>>
>>
>
>
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