Oh...
I just thought of something. The hover method is actually supposed to have
two functions built into it. One for over, and the other for out. I wonder
if that's why you're getting the error. Should look like this:
$(".swapImages").hover(function() {
var newSRC = $(this).attr("rel");
$(this).attr("src",newSRC);
},function(){
// something else goes here
});
-----Original Message-----
From: [email protected] [mailto:[EMAIL PROTECTED] On
Behalf Of Danjojo
Sent: Wednesday, September 26, 2007 8:17 AM
To: jQuery (English)
Subject: [jQuery] g has no properties?
I am doing a simple imageChange onLinkHover...
I get the following error in Firebug everytime I hover over a link.
But the image swaps work GREAT in all browsers.
Except for the fact I see the error getting thrown in the browsers I am
fine.
g has no properties
handleHover(Object type=mouseout target=a.showPic)jquery-svn.js (line
11)
e(Object type=mouseout target=a.showPic)jquery-svn.js (line 11)
e()jquery-svn.js (line 11) [Break on this error]
eval(function(p,a,c,k,e,r){e=function(c)
{return(c<a?'':e(parseInt(c/a)))+((c=c%a...
The jQuery code to swap images is:
$(".showPic").hover(function() {
$("#imgLinkAct").attr("src", "images/cylinder.jpg");
});
$(".showPic2").hover(function() {
$("#imgLinkAct").attr("src", "images/mgp_swap.jpg");
});
$(".showPic3").hover(function() {
$("#imgLinkAct").attr("src", "images/mhc_swap.jpg");
});
$(".showPic4").hover(function() {
$("#imgLinkAct").attr("src", "images/shock_swap.jpg");
});
$(".showPic5").hover(function() {
$("#imgLinkAct").attr("src", "images/emy2_swap.jpg");
});
$(".showPic6").hover(function() {
$("#imgLinkAct").attr("src", "images/ncy2_swap.jpg");
});
$(".showPic7").hover(function() {
$("#imgLinkAct").attr("src", "images/crq_swap.jpg");
});
$(".showPic8").hover(function() {
$("#imgLinkAct").attr("src", "images/clean_room_swap.jpg");
});
});