[jQuery] Re: trying to do Math.min on 3 tds by excluding if one = 0

Thanks , great solution.
i figured out on on my own that is quite different. i don't know which
is the best i terms of performance.
i create an array "numbArray" first of the elements then i do this.

var index= $.inArray(0, numbArray);
if(index== -1)
   {
     //Value not found in the array.
   }
else
   {
     numbArray.splice(index,1);
   }

var ithis = Math.min.apply(Math, numbArray);


Thanks for your solution.

Happy new year.

On Jan 1, 7:45 pm, Šime Vidas <[email protected]> wrote:
> This shoud do the job...
>
> $("tr." + i).each(function() {
>         var ithis = $(this).find("td:lt(3)").map(function() {
>                 if ($(this).html() === "0") {
>                         return null;
>                 } else {
>                         return this;
>                 }
>         }).min();
>         $(this).find("td.r1").empty().append(roundVal(ithis));
>
> });
>
> so, you select the first 3 cells, and then do the map function, which
> is similar to each... for every selected cell, if its content is "0",
> then "deselect" it... so after the map function, you only have those
> cells that doesn't contain "0", on them you run min()....