the variable name/reference is "$spn" so it would be:
$("p").append($spn);
your line of
$("p").append("spn")
does exactly what you told it to do :-)
On Jan 18, 2:34 pm, Mircea <[email protected]> wrote:
> I've added
>
> $("p").append("spn")
>
> It ads only the text spn at the bottom of the text. I probably did not
> used the append function right to pass the variable to p.
> Thanx
