I found a solution and posted it here: http://groups.google.com/group/jquery-ui/browse_thread/thread/5721073a70f5fc63/10491f2234701ca2
On Nov 2, 6:49 pm, delayedinsanity <[email protected]> wrote: > I read this thread > here:http://groups.google.com/group/jquery-ui/browse_thread/thread/e7658b6... > before posting, but I'm not having any luck with this... I'm a PHP > programmer, not AJAX, so I'm admittedly very clueless on the whole > subject. > > I gave it a quick attempt using PHP to determine how thetabsshould > be loaded, but the instant I modify > > jQuery(document).ready(function($) { > $("#tabs").tabs(); > > }); > > to look like > > jQuery(document).ready(function($) { > $("#tabs").tabs( 'select', 2 ); > > }); > > which according to the documentation I thought would load thetabs > with tab 3 selected. Except that it breaks. Thetabsfail completely. > I can't pass any arguments to .tabswithout it failing on me, and I've > tried select, load, even various other ones that have no bearing on my > situation just to see. :( > > So what I need to know, and trust me I've googled this with absolutely > no luck, is how if I submit aformon tab a b or c, how I can have the > same tab load that theformwas submitted from. -- You received this message because you are subscribed to the Google Groups "jQuery UI" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/jquery-ui?hl=.
