[css-easing-2] Whoops, use the *last* output when multiple points have the same input, rather than the *largest* output.

Author: tabatkins

css-easing-2/Overview.bs

@@ -299,7 +299,7 @@ Output</h4>
 
   3. If at least one of |points| has an [=input progress value=]
     matching |inputProgress|,
-    return the largest [=output progress value=] from among them.
+    return the [=output progress value=] of the last such point.
 
   4. Otherwise, find two [=linear()/control points=],
     |A| and |B|,
@@ -317,11 +317,9 @@ Output</h4>
       If |A| and |B| have the same [=input progress value=],
       return |B|'s [=output progress value=].
 
-    3. Otherwise, let |A| be the [=linear()/control point=]
-      with the largest [=output progress value=]
+    3. Otherwise, let |A| be the last [=linear()/control point=]
       whose [=input progress value=] is smaller than |inputProgress|,
-      and let |B| be the [=linear()/control point=]
-      with the smallest [=output progress value=]
+      and let |B| be the first [=linear()/control point=]
       whose [=input progress value=] is larger than |inputProgress|.
 
   5. Linearly interpolate (or extrapolate) |inputProgress|