Tooltip: Ignore disabled checks when closing. Fixes #8758 - Tooltip: Tooltip is shown, but not hidden if element has class=ui-state-disabled.

(cherry picked from commit 498aadf)

Author: scottgonzalez

tests/unit/tooltip/tooltip_core.js

@@ -94,4 +94,17 @@ test( "form containing an input with name title", function() {
 	equal( $( ".ui-tooltip" ).length, 0, "no tooltip for form" );
 });
 
+test( "tooltip on .ui-state-disabled element", function() {
+	expect( 2 );
+
+	var container = $( "#contains-tooltipped" ).tooltip(),
+		element = $( "#contained-tooltipped" ).addClass( "ui-state-disabled" );
+
+	element.trigger( "mouseover" );
+	equal( $( ".ui-tooltip" ).length, 1 );
+
+	container.empty();
+	equal( $( ".ui-tooltip" ).length, 0 );
+});
+
 }( jQuery ) );

ui/jquery.ui.tooltip.js

@@ -299,7 +299,7 @@ $.widget( "ui.tooltip", {
 		if ( !event || event.type === "focusin" ) {
 			events.focusout = "close";
 		}
-		this._on( target, events );
+		this._on( true, target, events );
 	},
 
 	close: function( event ) {