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Copy pathp060.py
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83 lines (65 loc) · 2.81 KB
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from euler import timeit
from math import floor, log10
is_prime = 0
def prime_sieve(lim):
global is_prime
is_prime = [True]*(lim+1)
is_prime[0] = is_prime[1] = False
for n in range(2, lim+1):
if is_prime[n]:
for m in range(2*n, lim+1, n):
is_prime[m] = False
@timeit
def solve():
prime_sieve(10**8)
print('sieve done')
lim = 10000
for p1 in range(2, lim):
if is_prime[p1]:
for p2 in range(p1+1, lim):
if is_prime[p2] and is_prime_pair(p2, p1):
for p3 in range(p2+1, lim):
if is_prime[p3] and is_prime_pair(p3, p1) and is_prime_pair(p3, p2):
for p4 in range(p3+1, lim):
if is_prime[p4] and is_prime_pair(p4, p1) and is_prime_pair(p4, p2) and is_prime_pair(p4, p3):
print(p1, p2, p3, p4)
for p5 in range(p4+1, lim):
if is_prime[p5] and is_prime_pair(p5, p1) and is_prime_pair(p5, p2) and is_prime_pair(p5, p3) and is_prime_pair(p5, p4):
print(p1, p2, p3, p4, p5)
return None
def is_prime_pair(n1, n2):
return is_prime[int(str(n1)+str(n2))] and is_prime[int(str(n2)+str(n1))]
@timeit
def solve_op():
lim = 10000
prime_sieve(lim)
print('sieve done')
for p1 in range(3, lim, 2):
if is_prime[p1]:
for p2 in range(p1+2, lim, 2):
if is_prime[p2] and prime_pair(p2, p1):
for p3 in range(p2+2, lim, 2):
if is_prime[p3] and prime_pair(p3, p1) and prime_pair(p3, p2):
for p4 in range(p3+2, lim, 2):
if is_prime[p4] and prime_pair(p4, p1) and prime_pair(p4, p2) and prime_pair(p4, p3):
print(p1, p2, p3, p4)
for p5 in range(p4+2, lim, 2):
if is_prime[p5] and prime_pair(p5, p1) and prime_pair(p5, p2) and prime_pair(p5, p3) and prime_pair(p5, p4):
print(p1, p2, p3, p4, p5)
print('PE60 Ans: %d' % sum((p1, p2, p3, p4, p5)))
return None
# def prime_pair(n1, n2):
# return prime(int(str(n1)+str(n2))) and prime(int(str(n2)+str(n1)))
def prime_pair(n1, n2):
t1 = n1*(10**floor(log10(n2)+1)) + n2
t2 = n2*(10**floor(log10(n1)+1)) + n1
return prime(t1) and prime(t2)
def prime(n):
lim = round(n**0.5)
for i in range(2, lim+1):
if n%i == 0:
return False
return True
if __name__ == '__main__':
# solve()
solve_op()