just a thought...code will be executed after the second call..
var oneCall = false;
function fn(json){
if(!oneCall){
oneCall = true;
return;
}
//code here
}
$.getJSON("url1", {}, fn);
$.getJSON("url2", {}, fn);
or you could put the second ajax call inside the function of the first one
or the other way around...
On 8/16/07, Jones <[EMAIL PROTECTED]> wrote:
>
>
> Hello,
>
> the following code provides one callback per ajax request:
>
> $.getJSON("url1", {}, function(json) {
> do something...
> });
> $.getJSON("url2", {}, function(json) {
> do something...
> });
>
> The problem is, that I need to call a function when both ajax requests
> are finished.
>
> Has anybody an idea?
>
>
> Another question: Does anybody know a german jQuery group or something
> similar?
>
> Jones
>
>