Andy,
Are you sure you used $form? I see this is what you have commented out:
// $(form).before(data.split('!!!')[1]);
That should work if you call it like this:
$form.before(data.split('!!!')[1]);
Note the use of $form instead of $(form).
Based on what you've got in your workaround, this is how I would code
it using ajaxForm:
$('.commentForm form').ajaxForm({
clearForm: true,
beforeSubmit: function(arr, $form, opts) {
var vals = $form.find('[EMAIL PROTECTED],[EMAIL
PROTECTED]').fieldValue();
if (!vals[0] || !vals[1]) {
alert('Both name and comment are required');
return false;
}
},
success: function(data, status, $form) {
$form.parent().before(data).prev('.singleComment').slideDown();
}
});
Mike
On 8/27/07, Andy Matthews <[EMAIL PROTECTED]> wrote:
>
> Yep...
>
> You're welcome to take a look at my final code.
>
