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Snailclimb merged 1 commit into from
Apr 24, 2025
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修改文章语句错误 #2665

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2 changes: 1 addition & 1 deletion docs/java/concurrent/java-concurrent-questions-01.md
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Expand Up @@ -403,7 +403,7 @@ Process finished with exit code 0

我们分析一下上面的代码为什么避免了死锁的发生?

线程 1 首先获得到 resource1 的监视器锁,这时候线程 2 就获取不到了。然后线程 1 再去获取 resource2 的监视器锁，可以获取到。然后线程 1 释放了对 resource1、resource2 的监视器锁的占用，线程 2 获取到就可以执行了。这样就破坏了破坏循环等待条件，因此避免了死锁。
线程 1 首先获得到 resource1 的监视器锁,这时候线程 2 就获取不到了。然后线程 1 再去获取 resource2 的监视器锁，可以获取到。然后线程 1 释放了对 resource1、resource2 的监视器锁的占用，线程 2 获取到就可以执行了。这样就破坏了循环等待条件，因此避免了死锁。

## 虚拟线程

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